Ansys APDL (经典)完整框架分析—Ansys经典培训
2017-03-18 by:CAE仿真在线 来源:互联网
Ansys经典培训 选仿真在线
这是一个Ansys APDL (经典)完整分析框架,还在学习如何写apdl代码的同学,可以参考:
!********************提示********************************************
!第一步:建立框架结构模型
!第二步:框架结构施加重力荷载
!第三步:框架结构施加活荷载
!第四步:框架结构施加风荷载
!第五步:框架结构荷载组合运算
!第六步:框架结构模态分析
!第七步:框架结构屈曲特征值分析
!第八步:框架结构地震时程弹性分析
!第九步:结束
!采用地震波时间文件为:TIME.TXT
!采用地震波文件分别为:AC_X.TXT/AC_Y.TXT
FINISH
/CLEAR
/FILENAME,FRAME_SHEAR_WALL
/TITLE, FRAME_SHEAR_WALL
!**************************************************************************
!************************第一步********************************************
!********************框架结构建模型***************************************
/PREP7
!采用单位为N/m/S国际单位制
!定义单元类型
ET,1,BEAM4
ET,2,SHELL63
!定义实常数
R,1,0.25,0.0052,0.0052,0.5,0.5
R,2,0.2025,0.0034,0.0034,0.45,0.45
R,3,0.06,0.0002,0.00045,0.3,0.2
R,4,0.25,0.25,0.25,0.25
R,5,0.1,0.1,0.1,0.1
!定义材料参数
MP,EX,1,3.0E10
MP,NUXY,1,0.2
MP,DENS,1,2500
!关键点
*DO,II,1,1
K,1+(II-1)*20,0,0,(II-1)*6
K,2+(II-1)*20,6,0,(II-1)*6
K,3+(II-1)*20,12,0,(II-1)*6
K,4+(II-1)*20,17,0,(II-1)*6
K,5+(II-1)*20,0,5,(II-1)*6
K,6+(II-1)*20,6,5,(II-1)*6
K,7+(II-1)*20,12,5,(II-1)*6
K,8+(II-1)*20,17,5,(II-1)*6
K,9+(II-1)*20,0,10,(II-1)*6
K,10+(II-1)*20,6,10,(II-1)*6
K,11+(II-1)*20,12,10,(II-1)*6
K,12+(II-1)*20,17,10,(II-1)*6
K,14+(II-1)*20,6,1.875,(II-1)*6
K,16+(II-1)*20,6,3.125,(II-1)*6
K,18+(II-1)*20,6,1.875,3.9
K,20+(II-1)*20,6,3.125,3.9
*ENDDO
*DO,II,1,10
K,1+II*20,0,0,(II-1)*3+6
K,2+II*20,6,0,(II-1)*3+6
K,3+II*20,12,0,(II-1)*3+6
K,4+II*20,17,0,(II-1)*3+6
K,5+II*20,0,5,(II-1)*3+6
K,6+II*20,6,5,(II-1)*3+6
K,7+II*20,12,5,(II-1)*3+6
K,8+II*20,17,5,(II-1)*3+6
K,9+II*20,0,10,(II-1)*3+6
K,10+II*20,6,10,(II-1)*3+6
K,11+II*20,12,10,(II-1)*3+6
K,12+II*20,17,10,(II-1)*3+6
K,13+II*20,0,1.875,(II-1)*3+6
K,14+II*20,6,1.875,(II-1)*3+6
K,15+II*20,0,3.125,(II-1)*3+6
K,16+II*20,6,3.125,(II-1)*3+6
K,17+II*20,0,1.875,(II-1)*3+6+1.5
K,18+II*20,6,1.875,(II-1)*3+6+2
K,19+II*20,0,3.125,(II-1)*3+6+1.5
K,20+II*20,6,3.125,(II-1)*3+6+2
*ENDDO
*DO,II,11,11
K,1+II*20,0,0,(II-1)*3+6
K,2+II*20,6,0,(II-1)*3+6
K,3+II*20,12,0,(II-1)*3+6
K,4+II*20,17,0,(II-1)*3+6
K,5+II*20,0,5,(II-1)*3+6
K,6+II*20,6,5,(II-1)*3+6
K,7+II*20,12,5,(II-1)*3+6
K,8+II*20,17,5,(II-1)*3+6
K,9+II*20,0,10,(II-1)*3+6
K,10+II*20,6,10,(II-1)*3+6
K,11+II*20,12,10,(II-1)*3+6
K,12+II*20,17,10,(II-1)*3+6
K,13+II*20,0,1.875,(II-1)*3+6
K,14+II*20,6,1.875,(II-1)*3+6
K,15+II*20,0,3.125,(II-1)*3+6
K,16+II*20,6,3.125,(II-1)*3+6
K,17+II*20,0,1.875,(II-1)*3+6+1.8
K,18+II*20,6,1.875,(II-1)*3+6+2.5
K,19+II*20,0,3.125,(II-1)*3+6+1.8
K,20+II*20,6,3.125,(II-1)*3+6+2.5
*ENDDO
*DO,II,12,12
K,1+II*20,0,0,39.5
K,2+II*20,6,0,39.5
K,3+II*20,12,0,39.5
K,4+II*20,17,0,39.5
K,5+II*20,0,5,39.5
K,6+II*20,6,5,39.5
K,7+II*20,12,5,39.5
K,8+II*20,17,5,39.5
K,9+II*20,0,10,39.5
K,10+II*20,6,10,39.5
K,11+II*20,12,10,39.5
K,12+II*20,17,10,39.5
*ENDDO
*DO,II,2,13
L,(II-1)*20+1,(II-1)*20+2
L,(II-1)*20+2,(II-1)*20+3
L,(II-1)*20+3,(II-1)*20+4
L,(II-1)*20+5,(II-1)*20+6
L,(II-1)*20+6,(II-1)*20+7
L,(II-1)*20+7,(II-1)*20+8
L,(II-1)*20+9,(II-1)*20+10
L,(II-1)*20+10,(II-1)*20+11
L,(II-1)*20+11,(II-1)*20+12
L,(II-1)*20+5,(II-1)*20+9
L,(II-1)*20+6,(II-1)*20+10
L,(II-1)*20+3,(II-1)*20+7
L,(II-1)*20+7,(II-1)*20+11
L,(II-1)*20+4,(II-1)*20+8
L,(II-1)*20+8,(II-1)*20+12
*ENDDO
*DO,II,1,12
L,(II-1)*20+1,II*20+1
L,(II-1)*20+2,II*20+2
L,(II-1)*20+3,II*20+3
L,(II-1)*20+4,II*20+4
L,(II-1)*20+5,II*20+5
L,(II-1)*20+6,II*20+6
L,(II-1)*20+7,II*20+7
L,(II-1)*20+8,II*20+8
L,(II-1)*20+9,II*20+9
L,(II-1)*20+10,II*20+10
L,(II-1)*20+11,II*20+11
L,(II-1)*20+12,II*20+12
*ENDDO
*DO,II,1,1
L,(II-1)*20+14,(II-1)*20+18
L,(II-1)*20+16,(II-1)*20+20
*ENDDO
*DO,II,2,12
L,(II-1)*20+13,(II-1)*20+17
L,(II-1)*20+15,(II-1)*20+19
L,(II-1)*20+14,(II-1)*20+18
L,(II-1)*20+16,(II-1)*20+20
*ENDDO
A, 1, 21, 25, 5
*DO,II,2,12
A, (II-1)*20+1, II*20+1, II*20+5, (II-1)*20+5, (II-1)*20+15,
(II-1)*20+19, (II-1)*20+17, (II-1)*20+13
*ENDDO
*DO,II,1,12
A, (II-1)*20+2, II*20+2, II*20+6, (II-1)*20+6, (II-1)*20+16,
(II-1)*20+20, (II-1)*20+18, (II-1)*20+14
*ENDDO
*DO,II,1,12
A, II*20+1, II*20+2, II*20+6, II*20+5
A, II*20+2, II*20+3, II*20+7, II*20+6
A, II*20+3, II*20+4, II*20+8, II*20+7
A, II*20+5, II*20+6, II*20+10,II*20+9
A, II*20+6, II*20+7, II*20+11,II*20+10
A, II*20+7, II*20+8, II*20+12,II*20+11
*ENDDO
!立柱网格划分
LSEL,S,,,181,192!底层立柱
LATT,1,1,1
LESIZE,ALL,,,10
LMESH,ALL
LSEL,S,,,192,324!2~12层立柱
LATT,1,2,1
LESIZE,ALL,,,5
LMESH,ALL
!梁网格划分
LSEL,S,,,1,180
LATT,1,3,1,
LESIZE,ALL,,,8
LMESH,ALL
!剪力墙网格划分
LSEL,S,,,372!外剪力墙两端、内剪力墙顶端
LSEL,A,,,413
LSEL,A,,,461
LESIZE,ALL,,,8
LSEL,s,,,418!内剪力墙底端
LSEL,A,,,420
LESIZE,ALL,,,3
LSEL,s,,,325!内剪力墙底端内侧
LSEL,A,,,326
LESIZE,ALL,,,6
LSEL,S,,,375!剪力墙空洞顶部
LSEL,A,,,379
LSEL,A,,,383
LSEL,A,,,387
LSEL,A,,,391
LSEL,A,,,395
LSEL,A,,,399
LSEL,A,,,403
LSEL,A,,,407
LSEL,A,,,411
LSEL,A,,,415
LSEL,A,,,419
LSEL,A,,,423
LSEL,A,,,427
LSEL,A,,,431
LSEL,A,,,435
LSEL,A,,,439
LSEL,A,,,443
LSEL,A,,,447
LSEL,A,,,451
LSEL,A,,,455
LSEL,A,,,459
LSEL,A,,,463
LESIZE,ALL,,,2
!剪力墙网格划分
ASEL,S,,,1,24
AATT,1,4,2
AMESH,ALL
!楼板网格划分
ASEL,S,,,25,96
AATT,1,5,2
AMESH,ALL
NSEL,S,LOC,Z,0!选取模型底端节点
D,ALL,ALL!施加位移约束
ALLSEL,ALL!重新选取所有节点
/eshape,1.0
/VIEW,1,1,1,1
/ANG,1,270,XM,0
/REPlot
FINISH
!**************************************************************************
!************************第二步********************************************
!********************框架结构施加重力荷载*********************************
!框架结构施加重力荷载
FINISH
/SOLU
ANTYPE,STATIC
NSEL,S,LOC,Z,0!选取模型底端节点
D,ALL,ALL!施加位移约束
ALLSEL,ALL!重新选取所有节点
ACEL,0,0,9.8
SOLVE
FINISH
/POST1
SET,FIRST
PLNSOL,U,Z,0,1
FINISH
!Ansys经典培训 选仿真在线
!**************************************************************************
!************************第三步********************************************
!*************框架结构施加楼面活荷载D=3KN/M^2*****************************
!框架结构施加楼面活荷载D=3KN/M^2
FINISH
/SOLU
ANTYPE,STATIC
NSEL,S,LOC,Z,0!选取模型底端节点
D,ALL,ALL!施加位移约束
ALLSEL,ALL!重新选取所有节点
ACEL,0,0,9.8
SOLVE
FINISH
/POST1
SET,FIRST
PLNSOL,U,Z,0,1
FINISH
!**************************************************************************
!************************第四步********************************************
!***********框架结构施加风荷载(基本风压=0.25KN/M^2,体形系数为1.0**********
!框架结构施加风荷载(先Y方向,后X方向)分两次分别施加
FINISH
/SOLU
ANTYPE,STATIC
*DIM,LOAD_1,ARRAY,12
LOAD_1(1)=3.78,2.16,2.39,2.57,2.72,2.84,2.95,3.17,3.20,3.29,3.39,3.51
*DIM,LOAD_2,ARRAY,12
LOAD_2(1)=7.56,4.32,4.78,5.14,5.44,5.68,5.90,6.34,6.40,6.58,6.76,7.02
*DIM,LOAD_3,ARRAY,12
LOAD_3(1)=6.93,3.96,4.38,4.71,4.99,5.21,5.41,5.81,5.87,6.03,6.20,6.44
*DIM,LOAD_4,ARRAY,12
LOAD_4(1)=3.15,1.80,1.99,2.14,2.27,2.37,2.46,2.64,2.67,2.74,2.82,2.93
*DIM,LOAD_A,ARRAY,12
LOAD_A(1)=3.15,1.80,1.99,2.14,2.27,2.37,2.46,2.64,2.67,2.74,2.82,2.93
*DIM,LOAD_B,ARRAY,12
LOAD_B(1)=6.30,3.60,3.98,4.28,4.54,4.74,4.92,5.28,5.34,5.48,5.64,5.86
*DIM,LOAD_C,ARRAY,12
LOAD_C(1)=3.15,1.80,1.99,2.14,2.27,2.37,2.46,2.64,2.67,2.74,2.82,2.93
*DO,II,1,12
FK,1+20*II,FY,LOAD_1(II)
*ENDDO
*DO,II,1,12
FK,2+20*II,FY,LOAD_2(II)
*ENDDO
*DO,II,1,12
FK,3+20*II,FY,LOAD_3(II)
*ENDDO
*DO,II,1,12
FK,4+20*II,FY,LOAD_4(II)
*ENDDO
SOLVE
FKDELE,ALL,ALL!第二次施加风荷载,删除第一次的。风有方向性
*DO,II,1,12
FK,1+20*II,FX,LOAD_A(II)
*ENDDO
*DO,II,1,12
FK,5+20*II,FX,LOAD_B(II)
*ENDDO
*DO,II,1,12
FK,9+20*II,FX,LOAD_C(II)
*ENDDO
SOLVE
FINISH
/POST1
SET,FIRST
PLNSOL,U,Y,0,1
SET,NEXT,
PLNSOL,U,X,0,1
FINISH
!**************************************************************************
!************************第五步********************************************
!************************框架结构荷载组合计算********************************
!框架结构荷载组合计算(1.D+L+WIND_X;2.D+L+WIND_Y)
!**************************************************************************
!************************第六步********************************************
!*******************框架结构模态分析**************************************
!框架结构模态分析
FINISH
/SOLU
ANTYPE,MODAL
MODOPT,LANB,6
MODOPT,LANB,6,0,0,,OFF
SOLVE
FINISH
/POST1
SET,LIST
SET,FIRST
PLDISP,0
SET,NEXT
PLSISP,0
SET,NEXT
PLSISP,0
SET,NEXT
PLSISP,0
SET,NEXT
PLSISP,0
SET,NEXT
PLSISP,0
FINISH
!**************************************************************************
!************************第七步********************************************
!****************框架结构特征值屈曲分析***********************************
!框架结构特征值屈曲分析
FINISH
/SOLU
ANTYPE,0
EQSLV,SPAR
PSTRES,ON
SOLVE
FINISH
/SOLU
ANTYPE,1
BUCOPT,LANB,6,0,0
MXPAND,6,0,0,1,0.001,
SOLVE
FINISH
/POST1
SET,LIST
SET,FIRST
PLDISP,2
SET,NEXT
PLDISP,2
SET,NEXT
PLDISP,2
SET,NEXT
PLDISP,2
SET,NEXT
PLDISP,2
SET,NEXT
PLDISP,2
FINISH
!**************************************************************************
!************************第八步********************************************
!****************框架结构地震时程分析*************************************
!框架结构地震时程分析
FINISH
*SET,NT,150
*DIM,TIME,,NT
*DIM,AC_X,,NT
*DIM,AC_Y,,NT
*CREATE,time
*VREAD,TIME,'TIME','txt',' ',1, , , , ,
,
(F6.2)
*END
/INPUT,time
*CREATE,ac_x
*VREAD,AC_X,'AC_X','txt',' ',1, , , , ,
,
(E10.3)
*END
/INPUT,ac_x
*CREATE,ac_y
*VREAD,AC_Y,'AC_Y','txt',' ',1, , , , ,
,
(E10.3)
*END
/INPUT,ac_y
!Ansys经典培训 选仿真在线
!分析选项设置与求解
/SOLU!进入求解器
ANTYPE,TRANS!定义分析类型
NSUBST,1, , ,1!定义荷载子步数
*DO,II,1,NT
!施加加速度荷载
ACEL,AC_X(II),AC_Y(II)
TIME,TIME(II)!设置时间点
SOLVE!求解
*ENDDO
FINISH
/POST26
NSOL,2,733,U,X,UX_1
NSOL,3,773,U,X,UX_2
NSOL,4,748,U,X,UX_3
NSOL,5,788,U,X,UX_4
NSOL,6,733,U,Y,UY_1
NSOL,7,773,U,Y,UY_2
NSOL,8,748,U,Y,UY_3
NSOL,9,788,U,Y,UY_4
PLVAR,2,3,4,5
PLVAR,6,7,8,9
FINISH
!**************************************************************************
!************************第九步********************************************
!****************整个框架结构所有分析过程结束*****************************
FINISH
转自博客:http://blog.sina.com.cn/s/blog_713bace90100w691.html
相关标签搜索:Ansys APDL (经典)完整框架分析—Ansys经典培训 Ansys有限元培训 Ansys workbench培训 ansys视频教程 ansys workbench教程 ansys APDL经典教程 ansys资料下载 ansys技术咨询 ansys基础知识 ansys代做 Fluent、CFX流体分析 HFSS电磁分析 Abaqus培训